擅长:python、mysql、java
<p>您可以通过循环列表来完成此操作:</p>
<pre><code>a = [[[ 0, 1, 2], [ 9,10,11]],
[[ 3, 4, 5], [12,13,14]],
[[ 6, 7, 8], [15,16,17]],
[[18,19,20], [27,28,29]],
[[21,22,23], [30,31,32]],
[[24,25,26], [33,34,35]]]
b = [[i for j in k for i in j ] for k in a]
print(b)
</code></pre>
<p>输出:</p>
^{pr2}$