对编程和尝试让我的移动方块检测宝藏随机产生在两个盒子之一
from Tkinter import *
import time
import random
window = Tk()
canvas = Canvas(window, width = 1200, height = 800, bg = 'yellow')
canvas.pack()
canvas.pack(padx = 10, pady = 10)
a1 = 120
a2 = 120
a3 = 60
a4 = 60
Lm1 = canvas.create_rectangle(a1, a2, a3, a4, fill = 'green')
b1 = 530
b2 = 530
b3 = 600
b4 = 600
Lm2 = canvas.create_rectangle(b1, b2, b3, b4, fill = 'green')
Tr1 = canvas.create_rectangle(85,85,85+10,85+10, fill = 'blue')
Tr2 = canvas.create_rectangle(560,560,560+10,560+10, fill = 'blue')
list1 = [Tr1, Tr2]
Treasure1 = random.choice(list1)
if Treasure1 == Tr1:
Tr1 = canvas.create_rectangle(85,85,85+10,85+10, fill = 'blue')
canvas.delete(Tr2)
if Treasure1 == Tr2:
Tr2 = canvas.create_rectangle(560,560,560+10,560+10, fill = 'blue')
canvas.delete(Tr1)
vx = 10.0
vy = 10.0
Ro1 = canvas.create_rectangle(20, 20, 20+10, 20+10)
def right():
canvas.coords(Ro1,x1+vx,y1,x2+vx,y2)
canvas.update()
time.sleep(0.1)
def left():
canvas.coords(Ro1, x1-vx,y1,x2-vx,y2)
canvas.update()
time.sleep(0.1)
def down():
canvas.coords(Ro1, x1,y1+vy,x2,y2+vy)
canvas.update()
time.sleep(0.1)
def up():
canvas.coords(Ro1, x1,y1-vy,x2,y2-vy)
canvas.update()
time.sleep(0.1)
for r in range(1, 12):
x1,y1,x2,y2 = canvas.coords(Ro1)
right()
for r in range(1,12):
x1,y1,x2,y2 = canvas.coords(Ro1)
down()
for r in range(1,5):
x1,y1,x2,y2 = canvas.coords(Ro1)
left()
这是我试过的,但没用,我想让它把宝藏拿走,如果它知道它在那里,然后向右移动,我不知道还能怎么做?在
^{pr2}$
没有理由创建两个正方形,然后在几行之后删除一个。只要创建一个你想要的。另外,你必须以某种方式跟踪坐标,或者每次移动时都要得到它们。下面的代码可以工作,但可能不是您想要的。我从帖子上看不出什么应该“向右移动”。希望这能让你朝着正确的方向开始。另外,在进一步进行GUI编程之前,先看看move而不是coordshttp://effbot.org/tkinterbook/canvas.htm,并考虑学习如何使用类。在
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