将Trie转换为JSON格式

2024-06-01 07:47:08 发布

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我计划使用trie数据结构实现自动完成功能。我想把trie转换成JSON格式。在

class Trie(object):
"""Class representing the structure of trie"""
   def __init__(self):
      self.children={}     #Links to other nodes
      self.isEndOfWord=False

这是我的trie程序的输出

^{pr2}$

其中:

'Z'-character stored in the trie node

<search_trie.Trie object at 0x7f3350f32c50> -points to other node

如何将其转换为JSON格式?我不希望对象地址出现在JSON中。如何从地址中提取节点并将其包含在JSON中?在

编辑: 这是我的密码。为了避免将节点存储为引用,我应该做什么修改?如果我可以存储实际的对象值而不是地址,那么将其转换为JSON将很简单。在

from functools import reduce
class Trie(object):
    """Class representing the trie"""
    def __init__(self):
        self.children={}
        self.isEndOfWord=False

    def add(self,char):  #Adds a character to dictionary and creates a new node 
        self.children[char]=Trie()

    def insert(self,word): #Insert a new word to the trie
        node=self
        for char in word:
            if char not in node.children:
                node.add(char)
            node=node.children[char]
        node.isEndOfWord=True

    def search(self, word): #Search for a particular word in a trie
        node = self
        for char in word:
            if char not in node.children:
                return False
            node = node.children[char]
        return node.isEndOfWord

    def all_suffixes(self,prefix):
        results = set()
        if self.isEndOfWord:
            results.add(prefix)
        if not self.children: 
            return results
        return reduce(lambda a, b: a | b, [node.all_suffixes(prefix + char) for (char, node) in self.children.items()]) | results

    def autocomplete(self, prefix):
        node = self
        for char in prefix:
            if char not in node.children:
                return set()
            node = node.children[char]
        return list(node.all_suffixes(prefix))

Tags: inselfnodejsonforprefixreturnif