擅长:python、mysql、java
<p>在Python中可以这样做:</p>
<pre><code>listOfNumbers = [1,2,3]
averagesOfNumbers = [0,0,0]
# In Python, we start counting from 0.
# So, 2 means 0,1 and in total, that
# is 2 numbers.
for i in range(2):
averagesOfNumbers [i] = (listOfNumbers [i] + listOfNumbers[i + 1])/2
print(averagesOfNumbers)
</code></pre>