回答此问题可获得 20 贡献值,回答如果被采纳可获得 50 分。
<p>如果有人能帮我解决这个问题,我将不胜感激。我有这个功能</p>
<pre><code>f(x) = r*x*(1-x)
</code></pre>
<p>我想为大约26个不同的r值重复定义,范围从3.8到3.85(我希望最终为这些函数绘制蛛网图并进行比较,我不想把r作为函数的参数)。所以我想把这26个函数存储在一个列表中,以后再访问它们。我有下面的代码,但是没有存储不同的函数定义,它只在列表中的所有26个位置存储第一个值r=3.8的函数。在</p>
^{pr2}$
<p>因此,这些打印语句的输出是:</p>
<pre><code>[3.8, 3.802, 3.804, 3.806, 3.808, 3.81, 3.812, 3.814, 3.816, 3.818, 3.82, 3.822, 3.824, 3.826, 3.828, 3.83, 3.832, 3.834, 3.836, 3.838, 3.84, 3.842, 3.844, 3.846, 3.848, 3.85]
[<function <lambda> at 0x0000000008739908>, <function <lambda> at 0x0000000008739978>, <function <lambda> at 0x00000000087399E8>, <function <lambda> at 0x0000000008739A58>, <function <lambda> at 0x0000000008739AC8>, <function <lambda> at 0x0000000008739B38>, <function <lambda> at 0x0000000008739BA8>, <function <lambda> at 0x0000000008739C18>, <function <lambda> at 0x0000000008739C88>, <function <lambda> at 0x0000000008739CF8>, <function <lambda> at 0x0000000008739D68>, <function <lambda> at 0x0000000008739DD8>, <function <lambda> at 0x0000000008739E48>, <function <lambda> at 0x0000000008739EB8>, <function <lambda> at 0x0000000008739F28>, <function <lambda> at 0x0000000008739F98>, <function <lambda> at 0x0000000008739828>, <function <lambda> at 0x000000000873D048>, <function <lambda> at 0x000000000873D0B8>, <function <lambda> at 0x000000000873D198>, <function <lambda> at 0x000000000873D208>, <function <lambda> at 0x000000000873D278>, <function <lambda> at 0x000000000873D2E8>, <function <lambda> at 0x000000000873D358>, <function <lambda> at 0x000000000873D128>, <function <lambda> at 0x00000000165452E8>]
-23.1
-23.1
</code></pre>
<p>我尝试了<a href="https://stackoverflow.com/questions/18915439/how-can-i-define-functions-in-a-for-loop">How can I define functions in a for loop?</a>中的所有建议,但还是无法使其发挥作用。有什么想法吗?我真的很感激。在</p>