Python编写zlib压缩d

Question

在开始之前，我使用的当前代码如下：

with open(classFileName,"a+"): as openFile
    fileData = openFile.readlines()
    try:
        fileData = zlib.decompress(str(fileData))
    except:
        pass

with open(classFileName,"a+") as openFile:
    openFile.write(fileData)

with open(classFileName,"a+") as openFile:
    fileData = []
    fileData = openFile.readlines()
    fileData.append(mergedData)

    fileData = sorted((a.strip().split() for a in fileData),key=operator.itemgetter(1))
    fileData = os.linesep.join(p[0] + ' ' + p[1] for p in fileData)

    fileData = str(fileData)
    zlib.compress(fileData)

with open(classFileName,"w") as openFile:
    openFile.write(fileData)

然而，这实际上抛出了一个错误，说在最后一行上应该有一个字符缓冲区对象。在

该文件的示例如下所示：

锐斯5号
约翰7
亚历克斯2

有什么建议或帮助吗？我想压缩以减少操纵分数。因为我这样做的原因看起来更好。不用担心原因。在

Answer 1

Python中的字符串是不能更改的（字节对象也是如此），因此，即使不查看文档，也可以推断出zlib.compress不能修改您的fileData{。上面的代码片段只记录了原始的fileData。在

来自the documentation：

zlib.compress(string[, level]) Compresses the data in string, returning a string contained compressed data. level is an integer from 0 to 9 controlling the level of compression; 1 is fastest and produces the least compression, 9 is slowest and produces the most. 0 is no compression. The default value is 6. Raises the error exception if any error occurs.

所以

 fileData = zlib.compress(fileData)

应该为你工作。在