擅长:python、mysql、java
<pre><code>from itertools import chain
from operator import itemgetter
def sortedchain(dicos, key):
return sorted(chain(v for d in dicos for v in d.values()), key=itemgetter(key))
dicos=[list1, list2, list3]
sortedvalues = sortedchain(dicos, 'timestamp')
</code></pre>
<p>所以dicos可以有任何长度</p>