随机单击按钮

Question

<ul> <li> <span class="_1OSdk"> <button class="_5f5mN -fzfL KUBKM yZn4P ">Segui già</button> </span> </li> <li> <span class="_1OSdk"> <button class="_5f5mN -fzfL KUBKM yZn4P ">Segui già</button> </span> </li> <li> <span class="_1OSdk"> <button class="_5f5mN -fzfL KUBKM yZn4P ">Segui già</button> </span> </li> <li> <span class="_1OSdk"> <button class="_5f5mN -fzfL KUBKM yZn4P ">Segui già</button> </span> </li> <li> <span class="_1OSdk"> <button class="_5f5mN -fzfL KUBKM yZn4P ">Segui già</button> </span> </li> <li> <span class="_1OSdk"> <button class="_5f5mN -fzfL KUBKM yZn4P ">Segui già</button> </span> </li> <li> <span class="_1OSdk"> <button class="_5f5mN -fzfL KUBKM yZn4P ">Segui già</button> </span> </li> <li> <span class="_1OSdk"> <button class="_5f5mN -fzfL KUBKM yZn4P ">Segui già</button> </span> </li> <li> <span class="_1OSdk"> <button class="_5f5mN -fzfL KUBKM yZn4P ">Segui già</button> </span> </li> <li> <span class="_1OSdk"> <button class="_5f5mN -fzfL KUBKM yZn4P ">Segui già</button> </span> </li> </ul>

Answer 1

现在我明白你的问题了：你试图获取这些按钮，然后从最后一个按钮一直单击到第一个按钮。
我认为这个片段应该有用：

#SEARCH FOR THE BUTTON THAT IT HAS TO CLICK

for button in reversed(driver.find_elements_by_css_selector("._5f5mN.-fzfL.KUBKM.yZn4P")):
    button.click()
    time.sleep(5)

# and the else-clause shouldn't be needed anymore

Answer 2

我创建了一个代码片段，它向每个按钮添加onclick事件。如果单击，脚本将检查单击的按钮后面有多少个按钮，并返回警报中的数字。 所以我不知道你怎么用JS。在

fiddle

// code from the fiddle
var buttons = document.getElementsByClassName('KUBKM');
for (var i = 0, len = buttons.length; i < len; i++) {
    buttons[i].onclick = function(e){
        var li = e.target.parentNode.parentNode;
        var i = 0;
        while(li != null){
            li = li.nextSibling;
            if(li != null){
                if(li.tagName == 'LI'){
                    i++;
                }
            }
        }
        //console.log('Button '+i+' was clicked');
        alert('Button '+i+' was clicked');
    }
}