擅长:python、mysql、java
<p>只需将列表展平为元组列表(初始列表包含元组的子列表):</p>
<pre><code>In [1251]: tupList = [[('commentID', 'commentText', 'date'), ('123456', 'blahblahblah', '2019')], [('45678', 'hello world', '2018'), ('0', 'text', '2017')]]
In [1252]: pd.DataFrame([t for lst in tupList for t in lst])
Out[1252]:
0 1 2
0 commentID commentText date
1 123456 blahblahblah 2019
2 45678 hello world 2018
3 0 text 2017
</code></pre>