用python打印多个if语句？

Question

我正在做一个简单的程序，要求3个输入，如果所有3个输入都匹配，则会打印欢迎消息。（姓名首字母==YNH，年龄==42，出生日期==1/27/74）。在

此外，还将打印用户名（youngnathanhather）的长度以及打印三个不同字符串之一的输入（颜色）。在

我遇到了一个问题，当我输入蓝色、粉色和黄色时，即使变量（颜色）不同，三个if语句都是真的并打印它们的字符串。在

也许我在这里漏掉了一大堆if语句，但有人知道这是怎么回事吗？我希望输入“Yellow”，只看到一个字符串打印。在

#checks if inputted information matches criteria.
#if all inputted information matches variable criteria
#(Initials == YNH, Age == 42, DOB == 1/27/74), then
#prints a Welcome message for the user.
if Initials == 'YNH':
    if Age == '42':
        if DOB == '1/27/74':
            print('Welcome Young Nathan Heather')
            print('Did you know that your name has  ' +str((len('YoungNathanHeather'))) +' letters.')
            #Asks for a color and prints a response based on if the color is pink, yellow, or blue
            color = input("If you could describe your mood in a color, what would it be ?")
            if color == 'blue' or 'Blue':
                print('According to my research Master, Blue and Yellow together  makes green. Green seems to be equal to money.')
            elif color == 'pink' or 'Pink':
                print('According to my research Master, Pink attracts women or makes a human into a women. Whatever comes first.')
            elif color == 'yellow' or "Yellow":
                print('According to my research Master, Yellow indicates a "mellow" mood. Prolong this mood if feasible.')
            else:
                print("My apologies Master. My research is shallow and I am not yet familiar with that mood's \"color\"")



        else:
            print('Sorry, Wrong Credentials Entered')
    else:
        print('Sorry, Wrong Credentials Entered')

else:
    print('Sorry, Wrong Credentials Entered')

Answer 1

当你说

        if color == 'blue' or 'Blue':

可以理解为

^{pr2}$

如果color == 'blue'为真，则为真；如果'Blue'为真，则为或。蓝色总是正确的。其他颜色也一样

你可以这样做：

        if color in [ 'blue', 'Blue']:

它将检查color是否存在于颜色列表中。但是‘蓝色’、‘蓝色’等呢？这里有一个更好的解决方案。在

        if color.lower() == "blue":

现在它可以匹配任何蓝色的大写字母！在

接下来，考虑这一部分：

if Initials == 'YNH':
    if Age == '42':
        if DOB == '1/27/74':
            print('Welcome Young Nathan Heather')
            ... ... ...
        else:
            print('Sorry, Wrong Credentials Entered')
    else:
        print('Sorry, Wrong Credentials Entered')

else:
    print('Sorry, Wrong Credentials Entered')

这是a lot of repetition，但也有很多不必要的缩进，这使得代码更难阅读和调试。为什么不是更像：

if Initials == 'YNH' and  Age == '42' and DOB == '1/27/74':
    print('Welcome Young Nathan Heather')
    ... ... ...
else:
     print('Sorry, Wrong Credentials Entered')

这样做，你的代码将更容易阅读，也更容易编写！在