如何从轮廓链_近似_简单到轮廓链约_无

Question

使用cv2.findContours()可以创建“稀疏”（链近似为简单）或“完整”（链约为无）的轮廓。如何将“稀疏”轮廓转换为“完整”轮廓？在

我没有我的轮廓的源图像（形状是已知的），只有轮廓，他们是“稀疏的”（链约_简单）。从这个“稀疏”表示，我想解决“全”（链约_无）表示，以便我可以使用它来访问其他图像的轮廓强度。在

我的临时解决方案（参见代码片段）是使用cv2.drawContours()，它从“稀疏”轮廓表示中提取所有轮廓像素。结果是一个图像，我可以从结果图像中提取索引，例如使用np.argwhere()。在

但是，考虑到{}在绘制结果图像之前可能已经在内部拥有了这些索引，这一额外步骤似乎有点不必要。我想我想要的是一个没有绘图部分的cv2.drawContours()的变体，或者一个输出“完整”轮廓表示而不是图像的选项。在

我的临时解决方案的另一个问题是它不能保持原始轮廓点的顺序。我想知道cv2.drawContours()是否能够在将结果展平为图像之前在内部重新创建完整、有效的轮廓？在

opencv中的其他函数是否提供了此功能，这些函数可能是cv2.drawContours()内部使用的一个更基本的函数？在

import numpy as np
import cv2

# shape (Y,X)
shape = np.array((5, 5))

# sparse contour (X,Y)
sparse_contours = [np.array(
    [[[1, 0]],
     [[1, 4]],
     [[3, 4]],
     [[3, 0]]], dtype=np.int32)]

def full_contour_from_contour(shape, contour):
    # switch shape from y,x to x,y
    shp = shape[[1,0]]
    arr = np.zeros(shp, dtype=np.int32)
    cv2.drawContours(arr, [contour], 0, 1, 1)
    idx = np.argwhere(arr==1)
    # reorder Y,X -> X,Y
    idx = idx[:, [1, 0]]
    # reshape to contour layout
    rows, cols = idx.shape
    idx = idx.reshape(rows, 1, cols)
    return idx.astype(np.int32)

full_contour = full_contour_from_contour(shape, sparse_contour)

# output
# these are correct pixels, with pixels in sparse contour also
# part of the full contour. However, the full contour is not 
# necessarily correct or even valid due to 
# lost information regarding point sequence along the contour)

[[[1 0]]

 [[2 0]]

 [[3 0]]

 [[1 1]]

 [[3 1]]

 [[1 2]]

 [[3 2]]

 [[1 3]]

 [[3 3]]

 [[1 4]]

 [[2 4]]

 [[3 4]]]

Answer 1

当您查看文档时：https://docs.opencv.org/2.4/modules/imgproc/doc/structural_analysis_and_shape_descriptors.html?highlight=findcontours#findcontours 它们之间的区别在于CHAIN_approach_NONE存储每个像素，CHAIN_approach_SIMPLE只存储构成轮廓线的端点。因此，您可以简单地构造连接轮廓中每对连续顶点的直线，以获得完整表示的近似值。属于线条的每个像素也属于轮廓。在

Answer 2

与suggestion一致的是，下面是一个似乎可以解决我的问题的代码片段。在

def full_from_sparse(contour):
    horizontal = np.array([1, 0], 'int')
    vertical = np.array([0, 1], 'int')
    diagonal = np.array([1, 1], 'int')
    def _get_points(p0, p1):
        # find all points on line connecting p0 and p1,
        # including p0, excluding p1
        # line must be horizontal, vertical or diagonal
        diff = p1-p0
        if np.max(np.abs(diff)) <= 1:
            # p0 and p1 are neighbor points
            # or duplicate points, i.e.g no in-between points
            return [p0]
        if diff[0] == 0:
            # vertical
            fac = diff[1]
            inc = vertical
        elif diff[1] == 0:
            # horizontal
            fac = diff[0]
            inc = horizontal
        elif diff[0] == diff[1]:
            # diagonal
            fac = diff[0]
            inc = diagonal
        else:
            raise Exception("points not connected", p0, p1)
        return [p0 + _fac*inc for _fac in range(0, fac, np.sign(fac))]

    full = []
    points = contour[:, 0, :]
    for i in range(len(points)-1):
        _points = _get_points(points[i], points[i+1])
        full.extend(_points)

    # add points from last segment, endpoint to startpoint
    _points = _get_points(points[-1], points[0])
    full.extend(_points)

    # reshape as contour
    full = np.array(full, dtype='int')
    rows, cols = full.shape
    return full.reshape(rows, 1, cols)