擅长:python、mysql、java
<p>您可以遍历外部列表,然后连接前两项的片段:</p>
<pre><code>def merge_names(lst):
for l in lst:
l[0:2] = [' '.join(l[0:2])]
merge_names(listoflist)
print(listoflist)
# [['BOTOS AUGUSTIN', 14, 'March 2016', 600, 'ALOCATIA'], ['HENDRE AUGUSTIN', 14, 'February 2015', 600, 'ALOCATIA']]
</code></pre>