用python通过hotmail发送电子邮件

Question

我想从我的服务器发送一封电子邮件。我正在尝试使用我已经拥有的hotmail帐户发送。

user = "myaddress@hotmail.com"
passwd = "xxxxxxxxx"

from_addr = "myaddress@hotmail.com"
to_addr = "someaddress@gmail.com"
smtp_srv = "smtp.live.com"

subject = "Home Server Uptime"
message = "The server has been online for: %s" %(uptime)

smtp = smtplib.SMTP(smtp_srv,587)
smtp.ehlo()
smtp.starttls()
smtp.ehlo()
smtp.login(user, passwd)
smtp.sendmail(from_addr, to_addr, message)
smtp.quit()

我得到这个错误：

Traceback (most recent call last):
  File "sendemail.py", line 23, in <module>
    smtp.starttls()
  File "/usr/lib/python2.7/smtplib.py", line 636, in starttls
    (resp, reply) = self.docmd("STARTTLS")
  File "/usr/lib/python2.7/smtplib.py", line 385, in docmd
    return self.getreply()
  File "/usr/lib/python2.7/smtplib.py", line 358, in getreply
    + str(e))
smtplib.SMTPServerDisconnected: Connection unexpectedly closed: [Errno 104] Connection reset by peer

我不知道怎么解决这个问题。

下面是Nathan建议的set_debuglevel（1）的输出：

send: 'ehlo [127.0.1.1]\r\n'
reply: '250-BLU0-SMTP190.blu0.hotmail.com Hello [my-ip-address]\r\n'
reply: '250-TURN\r\n'
reply: '250-SIZE 41943040\r\n'
reply: '250-ETRN\r\n'
reply: '250-PIPELINING\r\n'
reply: '250-DSN\r\n'
reply: '250-ENHANCEDSTATUSCODES\r\n'
reply: '250-8bitmime\r\n'
reply: '250-BINARYMIME\r\n'
reply: '250-CHUNKING\r\n'
reply: '250-VRFY\r\n'
reply: '250-TLS\r\n'
reply: '250-STARTTLS\r\n'
reply: '250 OK\r\n'
reply: retcode (250); Msg: BLU0-SMTP190.blu0.hotmail.com Hello [my-ip-address]
TURN
SIZE 41943040
ETRN
PIPELINING
DSN
ENHANCEDSTATUSCODES
8bitmime
BINARYMIME
CHUNKING
VRFY
TLS
STARTTLS
OK
send: 'STARTTLS\r\n'
Traceback (most recent call last):
  File "sendemail.py", line 24, in <module>
    smtp.starttls()
  File "/usr/lib/python2.7/smtplib.py", line 636, in starttls
    (resp, reply) = self.docmd("STARTTLS")
  File "/usr/lib/python2.7/smtplib.py", line 385, in docmd
    return self.getreply()
  File "/usr/lib/python2.7/smtplib.py", line 358, in getreply
    + str(e))
smtplib.SMTPServerDisconnected: Connection unexpectedly closed: [Errno 104] Connection reset by peer

Answer 1

试试这个

import email
import smtplib

msg = email.message_from_string('warning')
msg['From'] = "example1@hotmail.fr"
msg['To'] = "example2@hotmail.fr"
msg['Subject'] = "helOoooOo"

s = smtplib.SMTP("smtp.live.com",587)
s.ehlo() # Hostname to send for this command defaults to the fully qualified domain name of the local host.
s.starttls() #Puts connection to SMTP server in TLS mode
s.ehlo()
s.login('example1@hotmail.fr', 'pass')

s.sendmail("example1@hotmail.fr", "example2@hotmail.fr", msg.as_string())

s.quit()

Answer 2

在尝试启动TLS（smtp.starttls()）时，您的代码似乎失败了。我刚刚测试了smtp.live.com，并且我能够到达您试图登录的代码行，所以这可能是由于您的网络是如何设置的。

这是不相关的，但是根据smtplib文档，您必须在消息的开头添加from和to地址头：

parts = ("From: " + from_addr,
         "To: " + to_addr,
         "Subject: " + subject,
         "",
         message)    
msg = '\r\n'.join(parts)