我有一个在金字塔中创建应用程序的问题。当我试图用贴纸发球时,我得到:
File "/home/viraptor/blah/blah/__init__.py", line 23, in main
return config.make_wsgi_app()
File "/home/viraptor/pyramid/lib/python2.6/site-packages/pyramid/config.py", line 916, in make_wsgi_app
self.commit()
File "/home/viraptor/pyramid/lib/python2.6/site-packages/pyramid/config.py", line 491, in commit
self._ctx.execute_actions()
File "/home/viraptor/pyramid/lib/python2.6/site-packages/zope/configuration/config.py", line 626, in execute_actions
callable(*args, **kw)
File "/home/viraptor/pyramid/lib/python2.6/site-packages/pyramid/config.py", line 1291, in register
derived_view = deriver(view)
File "/home/viraptor/pyramid/lib/python2.6/site-packages/pyramid/config.py", line 2681, in __call__
self.mapped_view(view))))))))
File "/home/viraptor/pyramid/lib/python2.6/site-packages/pyramid/config.py", line 2624, in inner
wrapped_view = wrapped(self, view)
File "/home/viraptor/pyramid/lib/python2.6/site-packages/pyramid/config.py", line 2693, in mapped_view
mapped_view = mapper(**self.kw)(view)
File "/home/viraptor/pyramid/lib/python2.6/site-packages/pyramid/config.py", line 2860, in __call__
view = self.map_nonclass(view)
File "/home/viraptor/pyramid/lib/python2.6/site-packages/pyramid/config.py", line 2876, in map_nonclass
ronly = requestonly(view, self.attr)
File "/home/viraptor/pyramid/lib/python2.6/site-packages/pyramid/config.py", line 2966, in requestonly
if len(args) - len(defaults) == 1:
zope.configuration.config.ConfigurationExecutionError: <type 'exceptions.TypeError'>: object of type 'NoneType' has no len()
in:
('/home/viraptor/blah/blah/__init__.py', 22, 'main', "config.add_route('customer', '/customer/{customer_id}', view='blah.views.customer.view', view_renderer='customer_view.mak', view_permission='view', traverse='/customer/{customer_id}')")
为什么会这样?我最近甚至没有改变这个配置,只是应用程序的其他部分。在
我怀疑您遇到了在新版本的Pyramid中修复的错误;您的回溯表明}是},否则代码分支无法到达,留下的可能是{}是{}。我发现以下提交到金字塔的操作为
args
或{None
,但是除非args
不是{defaults
添加了一个特定的测试:https://github.com/Pylons/pyramid/commit/f168197609169fb01b65adeb3eb59d069000fe2c
我假设您有一个没有任何默认值的方法,只有一个请求参数(
method(self, request)
),解决方法是添加一个带有默认值(method(self, request, dummy=None)
)的关键字参数。在免责声明:还没有机会使用金字塔,所以我的分析完全基于金字塔代码库。在
config.add_route
只接受1个位置参数,您的第二个参数应与pattern
一起使用关键字。在其次,我不认为}有相同的模式。使用} API documentation 中有解释。在
route
和{traverse
关键字可以定义root
应该从哪里开始。在^{不过,引发的错误异常可以提供更多信息。在
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