我有一个html代码如下:
<div class="abc">
<div class ="xyz"
<p> xyz </p>
</div>
<div class= "foo">
<p>foo</p>
<a class="btn btn-lg btn-success" href="www.google.com" role="button" name="click" id="click">Click me</a>
<div>
</div>
我如何在这里抓取Click me
按钮并使用Selenium进行单击。我使用了driver.find_element_by_id()
,但它不起作用,并给出了一个错误。在
我想我可能需要遍历div标记才能到达按钮。在
^{pr2}$错误:
raise exception_class(message, screen, stacktrace)
InvalidSelectorException: Message: u'The given selector abc is either invalid or does not result in a WebElement. The following error occurred:\nInvalidSelectorError: Compound class names not permitted' ; Stacktrace:
at FirefoxDriver.annotateInvalidSelectorError_ (file:///tmp/tmpXXYwwK/extensions/fxdriver@googlecode.com/components/driver_component.js:8879)
at FirefoxDriver.prototype.findElementInternal_ (file:///tmp/tmpXXYwwK/extensions/fxdriver@googlecode.com/components/driver_component.js:8910)
at FirefoxDriver.prototype.findChildElement (file:///tmp/tmpXXYwwK/extensions/fxdriver@googlecode.com/components/driver_component.js:8917)
at DelayedCommand.prototype.executeInternal_/h (file:///tmp/tmpXXYwwK/extensions/fxdriver@googlecode.com/components/command_processor.js:10884)
at DelayedCommand.prototype.executeInternal_ (file:///tmp/tmpXXYwwK/extensions/fxdriver@googlecode.com/components/command_processor.js:10889)
at DelayedCommand.prototype.execute/< (file:///tmp/tmpXXYwwK/extensions/fxdriver@googlecode.com/components/command_processor.js:10831)
-----
因为,
Click me
是一个链接,您可以用链接文本找到它,然后单击它:相关问题 更多 >
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