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<p>我对使用lambda筛选列表的理解是,该筛选器将返回列表中所有返回lambda函数True的元素。在这种情况下,对于下面的代码</p>
<pre><code>inputlist = []
inputlist.<a href="https://www.cnpython.com/list/append" class="inner-link">append</a>(["1", "2", "3", "a"])
inputlist.append(["4", "5", "6", "b"])
inputlist.append(["1", "2", "4", "c"])
inputlist.append(["4", "5", "7", "d"])
outputlist = filter(lambda x: (x[0] != "1" and x[1] != "2" and x[2] != "3"), inputlist)
for item in outputlist: print(item)
</code></pre>
<p>输出应该是</p>
<pre><code>['4', '5', '6', 'b']
['1', '2', '4', 'c']
['4', '5', '7', 'd']
</code></pre>
<p>但我得到的结果是</p>
<pre><code>['4', '5', '6', 'b']
['4', '5', '7', 'd']
</code></pre>
<p>如果我使用</p>
<pre><code>outputlist = filter(lambda x: (x[0] != "1" or x[1] != "2" or x[2] != "3"), inputlist)
</code></pre>
<p>我在这里干嘛这么傻?还是我的理解不正确?</p>