<p><code>form_valid</code>应该返回一个<code>HttpResponseRedirect</code><a href="https://github.com/django/django/blob/master/django/views/generic/edit.py#L57" rel="nofollow noreferrer">https://github.com/django/django/blob/master/django/views/generic/edit.py#L57</a>,在您的情况下,您永远不会返回。我不知道您在<code>#save</code>之后是否有任何代码,但是请看一下我在您的代码中所做的注释</p>
<pre><code>class CalcUpdate(SuccessMessageMixin, UpdateView):
model = Calc
template_name = 'calc/cru_template.html'
form_class = CalcForm
def archive_calc(self, object_id):
model_a = Calc.objects.get(id = object_id)
model_b = Calc()
for field in model_a._meta.fields:
setattr(model_b, field.name, getattr(model_a, field.name))
model_b.pk = None
model_b.save()
return self.get_success_url(idnumber = model_b.pk) # you never return this value
def form_valid(self, form):
#objects
if self.object.checked == True:
object_id = self.object.id
return HttpResponseRedirect(self.archive_calc(object_id)) # you never return a `HttpResponse`
#save -- If this is where you are saving... you can store the value from archive and return it after saving
def get_success_url(self, **kwargs):
if kwargs != None:
return reverse_lazy('detail', kwargs = {'pk': kwargs['idnumber']})
else:
return reverse_lazy('detail', args = (self.object.id,))
</code></pre>
<p>另外,您不需要手动复制字段,只需这样做(假设没有<code>unique</code>约束,因为如果有,您的版本也会失败):</p>
<pre><code> def archive_calc(self, object_id):
c = self.model.objects.get(id = object_id)
c.pk = None
c.save()
return self.get_success_url(idnumber = c.pk)
</code></pre>