擅长:python、mysql、java
<p>@Ashwini有正确的答案,但只要说如果值不是按任何顺序排列的,那么你可以这样做。在</p>
<pre><code>>>> items = ['jump','double blink']
>>> dictionary = collections.OrderedDict([("wink", 400), ("double blink", 10),
("close your eyes", 300), ("jump", 0)])
>>> keys = iter(dictionary)
>>> all(item in keys for item in items)
False
</code></pre>