擅长:python、mysql、java
<p>你可以这样做:</p>
<pre><code># list index
l_index=0
# iterate over all dictionary objects in dict1 list
for d in dict1:
# add a field "count" to each dictionary object with
# the appropriate value from the list
d["count"]=list1[l_index]
# increase list index by one
l_index+=1
</code></pre>
<hr/>
<p>此解决方案不会创建新列表。相反,它会更新现有的<code>dict1</code>列表。</p>