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<p>我试图从服务器的响应中获取有效的python列表,如下所示:</p>
<blockquote>
<p>window.__search.list=[{"order":"1","base":"LAW","n":"148904","access":{"css":"avail_yes","title":"\u042
2\u0435\u043a\u0441\u0442\u0434\u043e\u043a\u0443\u043c\u0435\u043d\u0442\u0430\u0434\u043e\u0441\u0442\u0443\u043f\u0435\u043d"},"title":"\"\u0410\u0440\u0431\u0438\u0442\u0440\u0430\u0436\u043d\u044b\u0439\u043f\u0440\u043e\u0446\u0435\u0441\u0441\u0443\u0430\u043b\u044c\u043d\u044b\u0439\u043a\u043e\u0434\u0435\u043a\u0441\u0420\u043e\u0441\u0441\u0438\u0439\u0441\u043a\u043e\u0439\u0424\u0435\u0434\u0435\u0440\u0430\u0446\u0438\u0438\" \u043e\u0442 24.07.2002 N 95-\u0424\u0417 (\u0440\u0435\u0434. \u043e\u0442 02.07.2013) (\u0441 \u0438\u0437\u043c. \u0438 \u0434\u043e\u043f.,\u0432\u0441\u0442\u0443\u043f\u0430 \u044e\u0449\u0438\u043c\u0438\u0432 \u0441\u0438\u043b\u0443 \u0441 01.08.2013)"}, ... }];</p>
</blockquote>
<p>我是通过切断窗户来做到的__搜索.list=使用<code>data = json.loads(re.search(r"(?=\[)(.*?)\s*(?=\;)", url).group(1))</code>从字符串中提取“and”;,然后它看起来像标准JSON:</p>
<blockquote>
<p>[{u'access': {u'css': u'avail_yes', u'title': u'\u0422\u0435\u043a\u0441\u0442\u0434\u043e\u043a\u04
43\u043c\u0435\u043d\u0442\u0430 \u0434\u043e\u0441\u0442\u0443\u043f\u0435\u043d'},u'title': u'"\u0410\u0440\u0431\u0438\u0442\u0440\u0430\u0436\u043d\u044b\u0439\u043f\u0440\u043e\u0446\u0435\u0441\u0441\u0443\u0430\u043b\u044c\u043d\u044b\u0439\u043a\u043e\u0434\u0435\u043a\u0441\u0420\u043e\u0441\u0441\u0438\u0439\u0441\u043a\u043e\u0439\u0424\u0435\u0434\u0435\u0440\u0430\u0446\u0438\u0438" \u043e\u0442 24.07.2002 N 95-\u0424\u0417 (\u04
40\u0435\u0434. \u043e\u0442 02.07.2013) (\u0441 \u0438\u0437\u043c. \u0438 \u0434\u043e
\u043f.,\u0432\u0441\u0442\u0443\u043f\u0430\u044e\u0449\u0438\u043c\u0438 \u0432 \u0441
\u0438\u043b\u0443 \u0441 01.08.2013)', u'base': u'LAW', u'order': u'1', u'n': u'148904'}, ... }]</p>
</blockquote>
<p>但有时,在迭代其他URL时,我会遇到如下错误:</p>
<pre><code>File "/Developer/Python/test.py", line 123, in order_search
data = json.loads(re.search(r"(?=\[)(.*?)\s*(?=\;)", url).group(1))
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/json/__init__.py", line 326, in loads
return _default_decoder.decode(s)
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/json/decoder.py", line 366, in decode
obj, end = self.raw_decode(s, idx=_w(s, 0).end())
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/json/decoder.py", line 382, in raw_decode
obj, end = self.scan_once(s, idx)
ValueError: Invalid \uXXXX escape: line 1 column 20235 (char 20235)
</code></pre>
<p>我该如何修复它,或者也许有另一种方法可以获得有效的JSON(最好使用本机库)?在</p>