擅长:python、mysql、java
<p>这将创建两个列表一个包含所有第一个元素,另一个包含所有第二个元素。在</p>
<pre><code>x_cord = map(int,re.findall("(?<=\()\d+",str1))
y_cord= map(int,re.findall("(?<=\,\s)\d+",str1))
x_cord
[8, 9, 10, 11, 14, 17, 20, 21, 22, 23, 1, 5, 8, 9, 10, 11, 14, 17, 20, 23, 1, 5, 8, 9, 14, 17, 20, 21, 22, 23, 1, 5, 8, 9, 10, 11, 14, 17, 20, 21, 22, 23]
y_cord
[5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 7, 7, 7, 7, 7, 7, 7, 7, 7, 7, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8]
</code></pre>