RuntimeError:没有活动异常可使用tweepy重新读取

Question

我正在使用一个基于twitter的实时情绪分析的python代码。 它应该可以工作，因为youtube上也有一个教程，但是在我的电脑上，我有一个错误：

File "<ipython-input-2-9dc468222105>", line 1, in <module>
         runfile('C:/Users/marco/Anaconda3/envs/coinlive/social_functions.py',
 wdir='C:/Users/marco/Anaconda3/envs/coinlive')

File "C:\Users\marco\Anaconda3\lib\site-packages\spyder\utils\site\sitecustomize.py",
 line 710, in runfile
         execfile(filename, namespace)

File "C:\Users\marco\Anaconda3\lib\site-packages\spyder\utils\site\sitecustomize.py",
 line 101, in execfile
         exec(compile(f.read(), filename, 'exec'), namespace)

File "C:/Users/marco/Anaconda3/envs/coinlive/social_functions.py", line 82,
 in <module>
         twitterStream.filter(track=["Donald Trump"])

File "C:\Users\marco\Anaconda3\lib\site-packages\tweepy\streaming.py", line
 450, in filter
         self._start(async)

File "C:\Users\marco\Anaconda3\lib\site-packages\tweepy\streaming.py", line
 364, in _start
         self._run()

File "C:\Users\marco\Anaconda3\lib\site-packages\tweepy\streaming.py", line
 297, in _run
         six.reraise(*exc_info)

File "C:\Users\marco\Anaconda3\lib\site-packages\six.py", line 693, in reraise
         raise value

File "C:\Users\marco\Anaconda3\lib\site-packages\tweepy\streaming.py", line
 266, in _run
         self._read_loop(resp)

File "C:\Users\marco\Anaconda3\lib\site-packages\tweepy\streaming.py", line
 327, in _read_loop
         self._data(next_status_obj)

File "C:\Users\marco\Anaconda3\lib\site-packages\tweepy\streaming.py", line
 300, in _data
         if self.listener.on_data(data) is False:

File "C:/Users/marco/Anaconda3/envs/coinlive/social_functions.py", line 39,
 in on_data
         tweet=" ".join(re.findall("[a-zA-Z]+", tweet))

File "C:\Users\marco\Anaconda3\lib\re.py", line 222, in findall
         return _compile(pattern, flags).findall(string)

TypeError: cannot use a string pattern on a bytes-like object

我认为这个错误与tweepy图书馆有关，我读了很多文章，但没有得到任何好的结果。在

这是我的代码：

^{pr2}$

Answer 1

您正在对字符串进行编码

tweet=all_data["text"].encode("utf-8")

然后试着逃跑关于芬德尔上面写着：

^{pr2}$

尝试不使用编码调用