回答此问题可获得 20 贡献值,回答如果被采纳可获得 50 分。
<p>我正试图打开并解析一个html页面。在Python2.7.8中,我没有问题:</p>
<pre><code>import urllib
url = "https://ipdb.at/ip/66.196.116.112"
html = urllib.urlopen(url).read()
</code></pre>
<p>一切都很好。但是我想转到Python3.4,在那里我得到了HTTP错误403(禁止)。我的代码:</p>
<pre><code>import urllib.request
html = urllib.request.urlopen(url) # same URL as before
File "C:\Python34\lib\urllib\request.py", line 153, in urlopen
return opener.open(url, data, timeout)
File "C:\Python34\lib\urllib\request.py", line 461, in open
response = meth(req, response)
File "C:\Python34\lib\urllib\request.py", line 574, in http_response
'http', request, response, code, msg, hdrs)
File "C:\Python34\lib\urllib\request.py", line 499, in error
return self._call_chain(*args)
File "C:\Python34\lib\urllib\request.py", line 433, in _call_chain
result = func(*args)
File "C:\Python34\lib\urllib\request.py", line 582, in http_error_default
raise HTTPError(req.full_url, code, msg, hdrs, fp)
urllib.error.HTTPError: HTTP Error 403: Forbidden
</code></pre>
<p>它适用于其他不使用https的url。</p>
<pre><code>url = 'http://www.stopforumspam.com/ipcheck/212.91.188.166'
</code></pre>
<p>没关系。</p>