擅长:python、mysql、java
<p>您可以使用<code>KeyboardInterrupt</code>异常,而不是定义自己的<code>SIGINT</code>处理程序:</p>
<pre><code>while input("Do you want to count? ").strip().casefold() == "yes":
try:
counter()
except KeyboardInterrupt:
print("You pressed ctrl-c")
</code></pre>