<p>下面是一种在正常分配标签后删除重复图例项的方法:</p>
<pre><code>representatives=[[[-100,40],[-50,20],[0,0],[75,-5],[100,5]], #made up some data
[[-60,80],[0,85],[100,90]],
[[-60,15],[-50,90]],
[[-2,-2],[5,95]]]
fig = plt.figure()
axes = fig.add_axes([0.1, 0.1, 0.8, 0.8]) # left, bottom, width, height (range 0 to 1)
axes.set_xlabel('x (m)')
axes.set_ylabel('y (m)')
for i, representative in enumerate(representatives):
axes.plot([e[0] for e in representative], [e[1] for e in representative],color='b', label='Representatives')
#make sure only unique labels show up (no repeats)
handles,labels=axes.get_legend_handles_labels() #get existing legend item handles and labels
i=arange(len(labels)) #make an index for later
filter=array([]) #set up a filter (empty for now)
unique_labels=tolist(set(labels)) #find unique labels
for ul in unique_labels: #loop through unique labels
filter=np.append(filter,[i[array(labels)==ul][0]]) #find the first instance of this label and add its index to the filter
handles=[handles[int(f)] for f in filter] #filter out legend items to keep only the first instance of each repeated label
labels=[labels[int(f)] for f in filter]
axes.legend(handles,labels) #draw the legend with the filtered handles and labels lists
</code></pre>
<p>结果如下:
<a href="https://i.stack.imgur.com/eTdMa.png" rel="noreferrer"><img src="https://i.stack.imgur.com/eTdMa.png" alt="enter image description here"/></a>
左边是上面脚本的结果。右边的图例调用已替换为<code>axes.legend()</code>。</p>
<p>优点是,您可以遍历大部分代码,只需正常地分配标签,而不必担心内联循环或<code>if</code>s。您还可以将其构建为legend或类似的包装器。</p>