pythonxml只获取直接子元素

Question

我有一个xml文件，如下所示：

<?xml version="1.0" encoding="utf-8"?>
<EDoc CID="1000101" Cname="somename" IName="iname" CSource="e1" Version="1.0">
<RIGLIST>
    <RIG RIGID="100001" RIGName="RgName1">
          <ListID>
            <nodeA nodeAID="1000011" nodeAName="node1A" nodeAExtID="9000011" />
            <nodeA nodeAID="1000012" nodeAName="node2A" nodeAExtID="9000012" />
            <nodeA nodeAID="1000013" nodeAName="node3A" nodeAExtID="9000013" />
            <nodeA nodeAID="1000014" nodeAName="node4A" nodeAExtID="9000014" />
            <nodeA nodeAID="1000015" nodeAName="node5A" nodeAExtID="9000015" />
            <nodeA nodeAID="1000016" nodeAName="node6A" nodeAExtID="9000016" />
            <nodeA nodeAID="1000017" nodeAName="node7A" nodeAExtID="9000017" />
          </ListID>
        </RIG>
    <RIG RIGID="100002" RIGName="RgName2">
          <ListID>
            <nodeA nodeAID="1000021" nodeAName="node1B" nodeAExtID="9000021" />
            <nodeA nodeAID="1000022" nodeAName="node2B" nodeAExtID="9000022" />
            <nodeA nodeAID="1000023" nodeAName="node3B" nodeAExtID="9000023" />
          </ListID>
        </RIG>
</RIGLIST>
</EDoc>

我需要搜索节点值RIGName，如果找到匹配，则打印出nodeName的所有值

示例： 搜索RIGName=“RgName2”应将所有值打印为node1B、node2B、node3B

到目前为止，我只能得到以下第一部分：

^{pr2}$

如何才能只获取直接子节点的值？在

Answer 1

从xml.etree切换到{a1}将为您提供一种一次性完成的方法，因为much better XPath query language support：

In [1]: from lxml import etree as ET

In [2]: tree = ET.parse('input.xml')

In [3]: root = tree.getroot()

In [4]: root.xpath('//RIG[@RIGName = "RgName2"]/ListID/nodeA/@nodeAName')
Out[4]: ['node1B', 'node2B', 'node3B']