使用通过python中的串行端口连接到笔记本电脑的GSM调制解调器接收到的正则表达式解析字符串

Question

这是我使用的一个函数，它通过串行端口与我的笔记本电脑相连，用来查询GSM调制解调器接收到的新消息。我创建了一个串行对象“phone”，我用它来读写数据。在

“phone”将数据读入列表x

当我收到一条新消息时，我得到的回复是这样的：

+CMTI: "SM",0

这里0是一个索引，它指示在SIM上存储消息的索引位置。 下面的代码用于轮询包含我正在读写的数据的列表x 从串行端口。我正在使用正则表达式来解析x，它已被转换为字符串myRegexableString，以查看是否收到通知。在

^{pr2}$

我想把上面的代码用于AT命令，检查网络注册。当我执行其他命令时，我也需要轮询新消息，或者任何与此相关的命令，但是为了这个问题，我将以网络注册为例。下面是它在不使用轮询函数的情况下正常运行的方式。在

AT+CREG? #command

+CREG: 0,1 #response

OK #status

这是密码。在

def register():
   print "Checking for network registration"
   phone.write(b'AT+CREG?\r')
   sleep()
   x=phone.read(50)
   sleep()
   print x

现在假设我在这里包含轮询，代码将更改为

def register():
       print "Checking for network registeration"
       phone.write(b'AT+CREG?\r')
       sleep()
       x=phone.read(50)
       poll(x)
       sleep()
       print x

我从修改后的代码得到的输出是

Checking for network registeration
Printing myRegexableString
'AT+CREG?\r\r\n+CREG: 0,1\r\n\r\nOK\r\n'
You have received a new message!
You have received a new message!
You have received a new message!
You have received a new message!
You have received a new message!
You have received a new message!
You have received a new message!
You have received a new message!
You have received a new message!
You have received a new message!
You have received a new message!
You have received a new message!
You have received a new message!
You have received a new message!
You have received a new message!
You have received a new message!
You have received a new message!
You have received a new message!
You have received a new message!
You have received a new message!
You have received a new message!
You have received a new message!
You have received a new message!
You have received a new message!
You have received a new message!
You have received a new message!
You have received a new message!
You have received a new message!
You have received a new message!
AT+CREG?

+CREG: 0,1

OK

为什么要打印“你收到了一条新消息！”这么多次？在

尤其是当我还没有收到新消息的时候！在

请帮忙。在

Answer 1

您只需使用regex.findall(myRegexableString)。这将返回匹配的组的列表，因此为数字。在

regex = re.compile(r'\+CMTI: "SM",(\d+)')

def poll(x):
    myRegexableString = "".join(x)
    print "Printing myRegexableString"
    pprint(myRegexableString)
    lst = regex.findall(myRegexableString)

我已经将re.compile()调用移出了函数，不需要每次都重新编译表达式。在

循环遍历myRegexableString中的每个字符，然后在一个匹配one的列表上循环，然后测试myRegexableString是否为True ish（如果它不是空的话）。这意味着对于输入中的每个字符，您将添加一个空匹配（表达式永远不会匹配单个字符串中的任何内容）。在