python urllib2 urlopen无法打开https lin

2024-10-01 17:40:41 发布

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我正在用python编写oauth脚本。 当我试图打开https链接“https://www.douban.com/service/auth2/token”时

错误如下:

Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/home/users/zhangxuan06/.jumbo/lib/python2.7/urllib2.py", line 126, in urlopen
    return _opener.open(url, data, timeout)
  File "/home/users/zhangxuan06/.jumbo/lib/python2.7/urllib2.py", line 400, in open
    response = self._open(req, data)
  File "/home/users/zhangxuan06/.jumbo/lib/python2.7/urllib2.py", line 418, in _open
    '_open', req)
  File "/home/users/zhangxuan06/.jumbo/lib/python2.7/urllib2.py", line 378, in _call_chain
    result = func(*args)
  File "/home/users/zhangxuan06/.jumbo/lib/python2.7/urllib2.py", line 1215, in https_open
    return self.do_open(httplib.HTTPSConnection, req)
  File "/home/users/zhangxuan06/.jumbo/lib/python2.7/urllib2.py", line 1177, in do_open
    raise URLError(err)
urllib2.URLError: <urlopen error [Errno 110] Connection timed out>

但是当我用浏览器打开这个链接时,它工作得很好,并且会给我一个响应消息。在

有人能帮我吗?泰铢

更新:我的代码非常简单

^{pr2}$

Tags: inpyhttpshome链接liblineopen

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