擅长:python、mysql、java
<p>实际上,连续的三个字母序列太少了,你可以列出它们:</p>
<pre><code>BAD3 = {
"qwe", "wer", "ert", "rty", "tyu", "yui", "uio", "iop",
"asd", "sdf", "dfg", "fgh", "ghj", "hjk", "jkl",
"zxc", "xcv", "cvb", "vbn" }
def qwertz(string):
return any(bad in string for bad in BAD3)
</code></pre>
<p>很原始,我知道。如果你愿意的话,你可以用一个函数来准备坏的集合。在</p>
<hr/>
<p>“qwer功能更新两次”,例如“WE计数两次”</p>
^{pr2}$