基于传递给constru的参数实现Python类

Question

我正在实现一个python类，它在构造函数中构造另一个对象，其类型是根据传递给它的参数确定的。例如，在下面的代码中，"workerA"具有类"MyAClass"的行为，"workerB"对象具有{}的行为。在

我使用这个方法而不是从基类派生不同的类，因为基类已经在另一个无法更改的代码中使用。因此，如果我希望基类的另一个行为与"MyBClass"行为一样，那么我只需要将参数dbtype = "MyBClass"传递给它。在

有没有更好的方法可以用来得到同样的结果？在

  import sys

  # MyAClass definition
  class MyAClass :

     def __init__(self, serverSettings):
        self._serverSettings = serverSettings

     def initialize(self):
        self._init = 1;
        print("Calling", sys._getframe(1).f_code.co_name)

     def add(self):
        self._init = 2;
        print("Calling", sys._getframe(1).f_code.co_name)

     def finalize(self):
        self._init = 3;
        print("Calling", sys._getframe(1).f_code.co_name)

     def __del__(self):
        print('Calling destructor of class ', self.__class__.__name__)


  # MyBClass definition
  class MyBClass :

     def __init__(self, serverSettings):
        self._serverSettings = serverSettings

     def initialize(self):
        self._init = 1;
        print("Calling", sys._getframe(1).f_code.co_name)

     def add(self):
        self._init = 2;
        print("Calling", sys._getframe(1).f_code.co_name)

     def finalize(self):
        self._init = 3;
        print("Calling", sys._getframe(1).f_code.co_name)

     def __del__(self):
        print('Calling destructor of class ', self.__class__.__name__)


  # The base class which will be called in main program
  class BaseClass :

     def __init__(self, serverSettings, dbtype = None):

        if(dbtype == None):
           self.__worker = MyAClass(serverSettings)
        elif(dbtype == "MyBClass") :
           self.__worker = MyBClass(serverSettings)
        else :
           print("Undefined type")

     def initialize(self):
        self.__worker.initialize()

     def add(self):
        self.__worker.add()

     def finalize(self):
        self.__worker.finalize()


  if __name__ == "__main__":

     serverSettings = dict()

     serverSettings["address"] = "localhost"
     serverSettings["name"] = "Testname"

     workerA = BaseClass(serverSettings)
     workerA.add()

     workerB = BaseClass(serverSettings, dbtype = "MyBClass")
     workerB.finalize()

Answer 1

我知道这不会产生和你原来的程序一样的输出，但是这样的东西对你有用吗？除非查询方法名（如上所述），否则应该得到功能相同的结果。在

class BaseClass :
    def __init__(self, serverSettings, dbtype=None):

        if(dbtype == None):
           self.__worker = MyAClass(serverSettings)
        elif(dbtype == "MyBClass") :
           self.__worker = MyBClass(serverSettings)
        else :
           print("Undefined type")

    def __getattribute__(self, x):
        settings = object.__getattribute__(self, '__dict__').get('_BaseClass__worker')
        return settings.__getattribute__(x)

或者，使用像这样的类抖动：

^{pr2}$

Answer 2

根据这些建议，我做了以下代码更改

  class BaseClass :

     def __init__(self, serverSettings, Classtype = MyAClass):

        authclasses = [MyAClass, MyBClass]
        if Classtype not in authclasses :
           self.__worker = MyAClass(serverSettings)
        else :
           self.__worker = MyBClass(serverSettings)

     def __getattribute__(self, x):
        settings = object.__getattribute__(self, '__dict__').get('_BaseClass__worker')
        return settings.__getattribute__(x)