擅长:python、mysql、java
<p><a href="https://docs.python.org/2.7/library/itertools.html#itertools.groupby" rel="nofollow">^{<cd1>}</a>可以做到。在</p>
<pre><code>from itertools import groupby
def key(x): return x[1]
input=[("xyz",100),("tao",90),("quinee",100)]
output = [
(list(string for string,index in group),index)
for index,group in groupby(sorted(input, key=key, reverse=True), key=key)]
assert output == [(["xyz","quinee"],100),(["tao"],90)]
</code></pre>