擅长:python、mysql、java
<p>我会这样做:</p>
<pre><code>regex_fundleverage = re.findall('(?<=x)\d+|\d+(?=x)',instrument_name, flags=re.IGNORECASE)
if funddirection == "Long" and regex_fundleverage:
fundleverage = "+" + regex_fundleverage[0] + "00"
if funddirection == "Short" and regex_fundleverage:
fundleverage = "-" + regex_fundleverage[0] + "00"
print "Fundleverage: %s" % fundleverage
</code></pre>