通过CGI从sqlite3检索数据时出错

2024-10-08 18:21:56 发布

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我试图构建一个非常简单的登录页面，它要求用户输入他的register_no、username和{}。当他按下提交按钮时。我试图检查它是现有用户还是新用户，并相应地显示一条消息。在

我的文件夹层次结构是这样的

prodicus@Acer:~/Downloads/souvik_refactoring$ tree
.
├── cgi-bin
│   ├── creating_user_base_table.py
│   ├── user_base.db
│   └── usr_check.py
├── index.html
└── keyCheck.py

1 directory, 5 files

我的尝试：

对于index.html

^{pr2}$

对于creating_user_base_table.py

#!/usr/bin/env python3.4

import sqlite3
import os

db_name = "user_base.db"

if db_name in os.listdir():
    print("removing the user_base.db and creating a fresh copy of it")
    os.system("rm user_base.db")

print("Creating the database")
conn = sqlite3.connect(db_name)
cur = conn.cursor()

user_table = "CREATE TABLE users(reg_no INTEGER PRIMARY KEY, user_name TEXT, pass TEXT)"

new_users = (
    (1081310251, 'admin', 'admin'),
    (1081310234, 'foo', 'admin123')
)

cur.execute(user_table)
print("table created")
cur.executemany('INSERT INTO users VALUES(?, ?, ?)', new_users)
conn.commit()
print("default users created \n\ndisplaying them")

cur.execute('SELECT * FROM users')
print(cur.fetchall())

最后usr_check.py

#/usr/bin/env python3.4

import cgi, cgitb
import os
import sqlite3

cgitb.enable()

form = cgi.FieldStorage()
register_no = form.getvalue('register_no')
username = form.getvalue('username')
passwd = form.getvalue('password')

print("Content-type:text/html\r\n\r\n")
print("<html>")
print("<head>")
print("<h1>Shit gets real here</h1>")
print("</head>")
print("<body>")
print('<div style = "text-align:center ; "')
# print("</div>")
print("")

conn = sqlite3.connect('user_base.db')
cur = conn.cursor()

## now to check whether the entered data is for
## -> new user 
## -> an old user

cur.execute('SELECT user_name FROM users WHERE register_no = ?', (register_no,))
rows = cur.fetchall()
print("<br><br>")
if len(rows) == 0:  
    print("<p>User : <b>", username , "</b> does not exist.</p>")
    cur.execute('INSERT INTO users VALUES(?, ?, ?)', (register_no, username, passwd))
    print("<p>User was created successfully</p>")
    print("Done")

else:
    print("<p>Welcome<b>", username ,"</b>. Good to have you back")
    print("<br><p>Your account details</p>")
    print("<ul>")
    print("<li>Register number : ", register_no, " </li>")
    print("<li>Username " , username, "</li>")
    print("</ul>")

错误日志：

prodicus@Acer:~/Downloads/souvik_refactoring$ python -m CGIHTTPServer
Serving HTTP on 0.0.0.0 port 8000 ...
127.0.0.1 - - [02/Nov/2015 12:43:23] "GET /index.html HTTP/1.1" 200 -
127.0.0.1 - - [02/Nov/2015 12:44:03] "GET /cgi-bin/usr_check.py?register_no=1081310234&username=foo&password=admin123 HTTP/1.1" 200 -
Traceback (most recent call last):
  File "/usr/lib/python2.7/CGIHTTPServer.py", line 252, in run_cgi
    os.execve(scriptfile, args, env)
OSError: [Errno 8] Exec format error
127.0.0.1 - - [02/Nov/2015 12:44:03] CGI script exit status 0x7f00

在此之后，sqlite3 insert using python and python cgi我拥有文件权限

prodicus@Acer:~/Downloads/souvik_refactoring$ ll
total 36
drwxrwxr-x  3 prodicus prodicus  4096 Nov  2 08:30 ./
drwxr-xr-x 15 prodicus prodicus 20480 Nov  2 11:29 ../
drwxrwxrwx  2 prodicus prodicus  4096 Nov  2 12:23 cgi-bin/
-rw-rw-r--  1 prodicus prodicus   629 Nov  2 08:38 index.html
-rwxrwxr-x  1 prodicus prodicus   463 Nov  2 08:29 keyCheck.py*

以及

prodicus@Acer:~/Downloads/souvik_refactoring/cgi-bin$ ll
total 20
drwxrwxrwx 2 prodicus prodicus 4096 Nov  2 12:23 ./
drwxrwxr-x 3 prodicus prodicus 4096 Nov  2 08:30 ../
-rwxrwxrwx 1 prodicus prodicus  710 Nov  1 23:12 creating_user_base_table.py*
-rwxrwxrwx 1 prodicus prodicus 2048 Nov  2 12:23 user_base.db*
-rwxrwxrwx 1 prodicus prodicus 1576 Nov  2 08:26 usr_check.py*

令人惊讶的是，cgitb没有显示错误。我哪里出错了？从早上开始我就一直在这上面打伤我的头！在


Tags： nopyregisterdbbasebinusrusername
1条回答
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1楼 · 发布于 2024-10-08 18:21:56

终于弄明白这是怎么回事了。犯了一个愚蠢的错误！感谢@cas让我来到这里。在

做了一个#/usr/bin/env python3.4而不是#!/usr/bin/env python3.4

第二，当脚本usr_check.py试图连接到数据库user_base.db时，我必须给出绝对路径

这就解决了我的问题。在

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