擅长:python、mysql、java
<p>我想你可以按列检索矩阵:</p>
<pre><code>def remove_feature():
remove_index = []
for index in range(0, len(countermatrix.T)):
if countermatrix[:, index].max() > 1:
remove_index.append(index)
return numpy.delete(countermatrix, remove_index, 1)
</code></pre>