擅长:python、mysql、java
<p>未执行<code>fsync()</code>调用。错误来自<code>open()</code>。为什么?因为您无法在Windows上打开目录。*</p>
<p>{a1}是这种行为^:</p>
<blockquote>
<p><strong>EACCES</strong></p>
<blockquote>
<p>Tried to open a read-only file for writing, file's sharing mode does not allow the specified operations, <strong>or the given path is a directory.</strong></p>
</blockquote>
</blockquote>
<p>(重点是我的)。<code>EACCES</code>权限被拒绝;它被用作<a href="http://blogs.msdn.com/b/oldnewthing/archive/2005/01/17/354399.aspx" rel="nofollow noreferrer">compatibility reasons</a>的通用“你不能这样做”错误。在</p>
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<p>*具体来说,您不能使用POSIX子系统打开一个目录;在Windows上可以用<a href="https://msdn.microsoft.com/en-us/library/windows/desktop/aa363858(v=vs.85).aspx" rel="nofollow noreferrer">^{<cd4>}</a>打开一个目录,但是这会给您一个句柄,根据<a href="https://msdn.microsoft.com/en-us/library/windows/desktop/aa365258(v=vs.85).aspx" rel="nofollow noreferrer">this list</a>不能传递给<a href="https://msdn.microsoft.com/en-us/library/windows/desktop/aa364439%28v=vs.85%29.aspx?f=255&MSPPError=-2147217396" rel="nofollow noreferrer">^{<cd5>}</a>,所以这仍然是不可能的。在</p>