用beauthoulsoup从多个同名类中获取第一个类

Question

我试图从this page中提取信息，它的HTML如下所示。在

我试图提取第一个class="currentServers"中的文本（示例：我从这行<span class="currentServers">745,807</span>得到745807

问题是行中有两个类名为class="currentServers"的跨接。我想得到行的第一列中的值。在

HTML格式：

<tr class="player_count_row" style="">
                            <td align="right">
                                <span class="currentServers">745,807</span>
                            </td>
                            <td align="right">
                                <span class="currentServers">836,540</span>
                            </td>
                            <td width="20">&nbsp;</td>
                            <td>
                                <a class="gameLink" onmouseover="GameHover( this, event, 'global_hover', {&quot;type&quot;:&quot;app&quot;,&quot;id&quot;:570,&quot;v6&quot;:1} );" onmouseout="HideGameHover( this, event, 'global_hover' )" href="http://store.steampowered.com/app/570/">Dota 2</a>
                            </td>
                        </tr>

我觉得我离得很近，但我想不通。在

这就是我所尝试的：

^{pr2}$

输出如下：

[u'346110', u'http://store.steampowered.com/app/346110/', u'745,807']
[u'230410', u'http://store.steampowered.com/app/230410/', u'745,807']
[u'252950', u'http://store.steampowered.com/app/252950/', u'745,807']
[u'482730', u'http://store.steampowered.com/app/482730/', u'745,807']
[u'252490', u'http://store.steampowered.com/app/252490/', u'745,807']
[u'4000', u'http://store.steampowered.com/app/4000/', u'745,807']
[u'444090', u'http://store.steampowered.com/app/444090/', u'745,807']
[u'359550', u'http://store.steampowered.com/app/359550/', u'745,807']
[u'588430', u'http://store.steampowered.com/app/588430/', u'745,807']
[u'374320', u'http://store.steampowered.com/app/374320/', u'745,807']
[u'8930', u'http://store.steampowered.com/app/8930/', u'745,807']
[u'107410', u'http://store.steampowered.com/app/107410/', u'745,807']
[u'238960', u'http://store.steampowered.com/app/238960/', u'745,807']
[u'304930', u'http://store.steampowered.com/app/304930/', u'745,807']
[u'10', u'http://store.steampowered.com/app/10/', u'745,807']
[u'72850', u'http://store.steampowered.com/app/72850/', u'745,807']
[u'289070', u'http://store.steampowered.com/app/289070/', u'745,807']
[u'105600', u'http://store.steampowered.com/app/105600/', u'745,807']
[u'377160', u'http://store.steampowered.com/app/377160/', u'745,807']
[u'236390', u'http://store.steampowered.com/app/236390/', u'745,807']
[u'292030', u'http://store.steampowered.com/app/292030/', u'745,807']
[u'227300', u'http://store.steampowered.com/app/227300/', u'745,807']
[u'386360', u'http://store.steampowered.com/app/386360/', u'745,807']
[u'236850', u'http://store.steampowered.com/app/236850/', u'745,807']
[u'364360', u'http://store.steampowered.com/app/364360/', u'745,807']
[u'381210', u'http://store.steampowered.com/app/381210/', u'745,807']
[u'363970', u'http://store.steampowered.com/app/363970/', u'745,807']
[u'453480', u'http://store.steampowered.com/app/453480/', u'745,807'

... ... ...

我要提取其周围有红色椭圆的值：

（appid，Current Players，Game Name）-我可以成功地获得每个游戏的appid和游戏名，但不能按顺序获取当前玩家

Answer 1

你为什么要用两个循环？在

如果没有，你可以尝试一个循环，当循环链接时，找到前一个tr，然后找到第一个td，其中包含你想要的玩家编号。在

示例：

for link in links:
        players = currentPlayers[0].text
        try:
            appid = link.get('onmouseover')
            appid = findAppIdFromStats(appid,'"id":' , ',"public":1')
            linkg = link.get('href')
        except AttributeError:
            r.append(["N/A","N/A","N/A"])
        r.append([appid, linkg, link.find_previous("tr", class_="player_count_row").find("td").get_text(strip=True)])