循环使用两个计数器

Question

我在家里用Python制作了一个基于文本的游戏，在玩家和敌人之间创建一个小部分的战斗时遇到了麻烦。战斗应该包括两个随机掷骰；一个是玩家的，一个是外星人的。如果外星人掷得比玩家高，那么+1应该被添加到外星人的赢球计数器中，如果玩家赢了+1应该被添加到玩家的赢球计数器中。在

我想发生的是，当玩家赢的计数器达到3时，循环将停止并产生一条消息，同样的情况也应该发生在外星人的赢球数达到3时，但我有困难使其工作。任何帮助都将不胜感激，谢谢！在

import random
from Tkinter import *

def Fight():

    player_wins = 0
    alien_wins = 0

    while player_wins <= 3:

        player_roll = random.randint(0, 10)
        alien_roll = random.randint(0, 7)

        if player_roll > alien_roll:
            contents.set("You manage to fire a shot of your laser pistol and the alien backs off.")
            player_wins += 1
            return

        elif alien_roll > player_roll:
            contents.set("The alien reaches out and strikes you with its claws.")
            alien_wins += 1
            return

        elif alien_roll == player_roll:
            contents.set("You both grapple eachother and eventually back off.")        
            return

            if player_wins == 3:
                contents.set("You manage to overcome the alien. It leaps from wall to wall and crawls into the vents.")
                win = True
                break
            elif alien_wins == 3:
                contents.set("You lose the fight to the alien. Game Over!")
                break

base = Tk()

contents = StringVar()
display = Message(base, textvariable = contents, relief=RAISED)
display.pack()

enterbutton = Button(base, text = 'Try Again', command = Fight).pack()

base.mainloop()

Answer 1

我清理了一些东西。通过使循环依赖于player_wins和{}同时是{}，修复了循环的主要问题。这样，每当其中一个命中3，循环终止，控制转到下面的if/else语句，该语句将设置优胜者。在

def Fight():    
    player_wins = 0
    alien_wins = 0

    while player_wins <= 3 and alien_wins <= 3:    
        player_roll = random.randint(0, 10)
        alien_roll = random.randint(0, 7)

        if player_roll > alien_roll:
            contents.set("You manage to fire a shot of your laser pistol and the alien backs off.")
            player_wins += 1
        elif alien_roll > player_roll:
            contents.set("The alien reaches out and strikes you with its claws.")
            alien_wins += 1
        else:
            contents.set("You both grapple eachother and eventually back off.")     

    if player_wins == 3:
        contents.set("You manage to overcome the alien. It leaps from wall to wall and crawls into the vents.")
        win = True
    else:
        contents.set("You lose the fight to the alien. Game Over!")

您也不需要那些break语句，因为这完全脱离了循环。您可能正在考虑continue，它只会转到循环的下一个迭代，但是即使这样也不需要，因为循环的整个内容只是一个if/else语句，因此只执行一个分支。在

另外，在elif中检查两个rolls是否相等是不必要的，因为您已经排除了两个都不大于/小于另一个，所以可以假设它们是相等的。最后一个if/else也一样，你可以检查谁拥有3。如果我们不在循环中，我们知道有人有3，所以我们只需要检查一个玩家的分数。在

Answer 2

当任一条件（points<；=3）为True时，您希望继续战斗（循环）。您需要向while循环添加另一个条件。在

你只想在战斗结束后从函数返回，所以删除所有这些返回，并在战斗结束后添加一个在循环之外的返回。只想在战斗结束后，你也只想创造信息。在

def Fight():

    player_wins = 0
    alien_wins = 0

    while player_wins <= 3 and alien_wins <= 3:

        player_roll = random.randint(0, 10)
        alien_roll = random.randint(0, 7)

        if player_roll > alien_roll:
            contents.set("You manage to fire a shot of your laser pistol and the alien backs off.")
            player_wins += 1

        elif alien_roll > player_roll:
            contents.set("The alien reaches out and strikes you with its claws.")
            alien_wins += 1

        elif alien_roll == player_roll:
            contents.set("You both grapple eachother and eventually back off.")        

    if player_wins == 3:
        contents.set("You manage to overcome the alien. It leaps from wall to wall and crawls into the vents.")
        win = True
    elif alien_wins == 3:
        contents.set("You lose the fight to the alien. Game Over!")
    return