擅长:python、mysql、java
<p>只需列出元组列表</p>
<pre><code>>>> chainpos.append((chainid,x, y, z))
>>> chainpos
[('A', 1.719, -25.217, 8.694), ('A', 2.934, -21.997, 7.084)]
>>> import itertools
>>> for id, coor in itertools.groupby(chainpos,lambda x:x[0]):
... print(id, [c[1:] for c in coor])
</code></pre>