Python21点计算玩家手数

Question

所以我试着数数多位选手的手数，然后互相比较。在

以下是我的主要代码：

def make_deck():
    # Randomly shuffle a deck
    import random
    cards = []
    for suit in ['H', 'C', 'S', 'D']:
        for num in ['A', '2', '3', '4', '5', '6', '7', '8', '9', 'T', 'J', 'Q',
                'K']:
            cards.append(num + suit)
    random.shuffle(cards)
    return cards
deck = make_deck()


num_of_players = int(input("How many players?: "))

def deal_blackjack(deck, num_of_players):
    # Deal two cards to a number of players
    hands = [[] for p in range(num_of_players)]
    i = -1
    for k in range(0,2):
        for h in hands:
            i += 1
            h.append(deck[i])
    return hands

pHands = deal_blackjack(deck, num_of_players)


def print_blackjack(pHands):
    # Prints Players with respective hand
    for i in range(len(pHands)):
        print('Player', i, ':', pHands[i])

def get_max(pHands): 
#Where I'm stuck at
    for i in range(pHands):
        total = 0

        pTotal = int(pHands[i][x][0])

我知道我必须使用pHands和一个循环来获取每只手的第一个字符，并将其转换为int ex.int（pHands[I#of hand][x#of 1st str][0]），然后将它加到total上

但我似乎不知道如何在玩家的每只手上实现它。在

前四名选手

玩家0:['3S'，'JH']总计=13

玩家1:['6C'，'JC']总计=16

玩家2:['4H'，'5D']总计=9

玩家3:['7D'，'AC']总计=18

#在

另外，我想比较每只手牌并选择一个赢家（在手的旁边会出现一个星号）。在

#在

前四名选手

玩家0:['3S'，'JH']

玩家1:['6C'，'JC']

玩家2:['4H'，'5D']

玩家3:['7D'，'AC']*

谢谢你的帮助！在

Answer 1

cards_dict = {'A':1, '2':2, '3':3, '4':4, '5':5, '6':6, '7':7, '8':8, '9':9, 'T':10, 'J':11, 'Q':12,'K':13}
def card_to_value(card):
    return cards_dict[card[1]]

def get_max(pHands): 
   for i in range(len(pHands)):
      pCards = pHands[i]
      pTotal[i] = card_to_value(pCards[0]) + card_to_value(pCards[1])
   return pTotal

def winner(pTotal):
    biggest_hand = max(pTotal)
    #if its a tie
    if pTotal.count(biggest_hand) > 1:
        #i don't know what happens
    else:
        return pTotal.index(biggest_hand)

Answer 2

您应该创建一个名为calculate_hand的方法，然后在那里完成工作。在

scores = {"A":1, "T":10, "J": 10, "K":10, "Q": 10, }
def calculate_hand(hand):
    hand_value = 0
    ace = False
    for card in hand:
        if card[0] == "A":
            ace =True;
        if card[:-1] in scores:  #used [:-1] insted of [0] because at first, thought it is 10 instead of T
            hand_value += scores[card[:-1]]
        else:
            hand_value += int(card[:-1])
    if ace and hand_value + 10 < 22:
        hand_value += 10
    return hand_value

hand1 = ['AD', 'AC']
hand2 = ['6C', 'JC']
hand3 = ['7D', 'AC']   
value1 = calculate_hand(hand1) #12
value2 = calculate_hand(hand2) #16
value3 = calculate_hand(hand3) #18

计算完每只手之后，只需比较calculate_hand返回的值。在

^{pr2}$

您应该很容易地将这些实现到您的代码中。在