擅长:python、mysql、java
<p>谢谢特莫罗</p>
<p>我刚刚找到了方法,就在这里(以防其他人和我一样对pyqt感到失望)</p>
<p>在mytablewidget.py
rom PyQt4导入QtGui
从PyQt4.QtCore导入Qt</p>
<p>类MyTableWidget(qtablegui.qtablegui)公司名称:</p>
<pre><code>parent = None
def __init__(self, parent=None):
self.parent = parent
super(MyTableWidget, self).__init__(parent)
def keyPressEvent(self, event):
key = event.key()
if key == Qt.Key_Return or key == Qt.Key_Enter:
print('clicked enter')
else:
super(MyTableWidget, self).keyPressEvent(event)
def setUI(self, ui_parent):
self.ui = ui_parent
</code></pre>
<p>在里面呢主.py在</p>
<p>导入系统
从PyQt4导入QtGui,QtCore,Qt
从我的接口导入Ui主窗口</p>
^{pr2}$