擅长:python、mysql、java
<p>我只是把别人在评论中已经说过的话放在一起。在</p>
<p>我还没有测试代码,但它应该能正常工作。在</p>
<pre><code><script type="text/javascript">
var myEvent = {
user_token: {
userid: 1
},
title: "test title",
privilege: "public"
};
console.log(myEvent)
$.ajax({
url: '/gallery/new_report/',
type: 'POST',
contentType: 'application/json; charset=utf-8',
data: {'eventValues': myEvent},
dataType: 'text',
success: function(result) {
alert(result);
},
error: function(ts) {
alert("fail");
}
});
</code></pre>
<p/>
<p>和python视图</p>
^{pr2}$