擅长:python、mysql、java
<p>试试这个</p>
<pre><code>from itertools import groupby
result = []
for key, group in groupby(warnstufe2, lambda x: x[0]):
for element in group:
a = element[1:4]
b = element[4:12]
c = [a,b]
result.append(c)
print (result)
</code></pre>