有没有比我更有经验的人能告诉我为什么下面的代码会冻结(挂起)窗户?它所要做的就是显示一个红色屏幕,并在窗口名称中更新其FPS。谢谢您!:)
import pygame
from pygame.locals import *
from pygame import Color
class Game():
""" Lets try to get this going by simple steps
One by one. First step, lets figure how to make a class
that can do the display stuff. Lord have mercy on my soul"""
runGame = True
def __init__(self, wi=256, hi=224, multii=3):
"""Initialization"""
pygame.init()
self.width = wi*multii
self.height = hi*multii
self.spritesize = 16*multii
self.clock = pygame.time.Clock()
self.fps = self.clock.get_fps()
self.screen = pygame.display.set_mode((self.width, self.height))
def mainLoop(self):
"""Loop through the main game routines
1. Drawing 2. Input handling 3. Updating
Then loop through it until user quits"""
while self.runGame:
self.clock.tick(12)
self.draw()
self.events()
def events(self):
"""Time to handle some events"""
events = pygame.event.get()
for e in events:
print e
if (e.type == pygame.QUIT) or
(e.type == KEYDOWN and e.key == K_ESCAPE):
self.runGame = False
def draw(self):
"""Draw and update the main screen"""
self.screen.fill(Color('red'))
pygame.display.set_caption('Grid2. FPS: '+str(self.fps))
pygame.display.update()
game = Game()
game.mainLoop()
在Game类中,您在
__init__
函数之外声明runGame
,而没有将self.runGame
用于减速。你也只在第一次创建游戏对象时更新FPS,因此它将保持相同的值。在解决方法:
runGame
减速并使其self.runGame
self.fps
。我已经在draw
函数下添加了它所以你的结束代码应该是这样的(在我更改的地方包括注释):
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