<p>我正在尝试为以下型号打开django管理。。在</p>
<pre><code>class FirstModel(models.Model):
name = models.CharField(max_length=100)
class SecondModel(models.Model):
name = models.CharField(max_length=100)
firstModel = models.ForeignKey(FirstModel, related_name='secondList')
class ThirdModel(models.Model):
name = models.CharField(max_length=100)
secondModel = models.ForeignKey(SecondModel, related_name='thirdList')
</code></pre>
<p>我想创造一个管理员py对于以下型号:。。在</p>
^{pr2}$
<p>我希望能够将SecondModel和ThirdModel编辑为FirstModel中的递归关系。但这是行不通的。我试着跟踪这个链接:[<a href="https://stackoverflow.com/questions/7615351/model-with-recursive-self-relation-in-djangos-admin][1]">Model with recursive self relation in Django's admin</a></p>
<p>[1]:<a href="https://stackoverflow.com/questions/7615351/model-with-recursive-self-relation-in-djangos-admin">Model with recursive self relation in Django's admin</a>。任何帮助都将不胜感激。谢谢!!在</p>