擅长:python、mysql、java
<p>如果基于空格定义单词,则可以使用以下方法:</p>
<pre><code>def containsNonAscii(s):
return any(ord(i)>127 for i in s)
words = sentence.split()
cleaned_words = [word for word in words if not containsNonAscii(word)]
cleaned_sentence = ' '.join(cleaned_words)
</code></pre>
<p>请注意,这将把重复的空白压缩成一个空格。在</p>