除去元音，除非它是单词的开头

Question

我试图删除字符串中元音的出现，除非它们是单词的开头。例如，"The boy is about to win"这样的输入应该输出Th by is abt t wn。任何帮助都将不胜感激！在

def short(s):
vowels = ('a', 'e', 'i', 'o', 'u')
noVowel= s
toLower = s.lower()
for i in toLower.split():
    if i[0] not in vowels:
        noVowel = noVowel.replace(i, '')        
return noVowel

Answer 1

一种方法是使用正则表达式替换前面没有单词边界的元音。另外，如果您的代码应该处理带有各种标点符号的任意文本，那么您可能需要考虑一些更有趣的测试用例。在

import re
s = "The boy is about to win (or draw). Give him a trophy to boost his self-esteem."
rgx = re.compile(r'\B[aeiou]', re.IGNORECASE)
print rgx.sub('', s)  # Th by is abt t wn (or drw). Gv hm a trphy t bst hs slf-estm.

Answer 2

可以对字符串的其余部分使用regex（忽略第一个字符）：

import re
s = 'The boy is about to win'
s = s[0] + re.sub(r'[aeiou]', '', s[1:])
print s # Th by s bt t wn

Answer 3

尝试：

>>> s = "The boy is about to win"
>>> ''.join(c for i, c in enumerate(s) if not (c in 'aeiou' and i>1 and s[i-1].isalpha()))
'Th by is abt t wn'

工作原理：

如果发电机：

^{pr2}$

发电机的关键部件是：

if not (c in 'aeiou' and i>1 and s[i-1].isalpha())

这意味着s中的所有字母都包括在内，除非它们不是（a）在s开头的元音，也不是（b）前面有一个非字母，这也意味着它们在单词的开头。在

重写为for循环

def short(s):
    new = ''
    prior = ''
    for c in s:
        if not (c in 'aeiou' and prior.isalpha()):
            new += c
        prior = c
    return new