<p>我知道有一个内置的xor操作符可以用Python导入。
我正在尝试执行xor加密/解密。到目前为止我有:</p>
<pre><code> def xor_attmpt():
message = raw_input("Enter message to be ciphered: ")
cipher = []
for i in message:
cipher.<a href="https://www.cnpython.com/list/append" class="inner-link">append</a>(bin(ord(i))[2::])#add the conversion of the letters/characters
#in your message from ascii to binary withoout the 0b in the front to your ciphered message list
cipher = "".join(cipher)
privvyKey = raw_input("Enter the private key: ")
keydecrypt = []
for j in privvyKey:
keydecrypt.append(bin(ord(j))[2::]) #same
keydecrypt = "".join(keydecrypt )#same
print "key is '{0}'" .format(keydecrypt) #substitute values in string
print "encrypted text is '{0}'" .format(cipher)
from operator import xor
for letter in message:
print xor(bool(cipher), bool(keydecrypt))
</code></pre>
<p>这:</p>
<pre><code>> for letter in message:
print xor(bool(cipher), bool(keydecrypt))
</code></pre>
<p>是我的Python开始出错的地方。</p>
<p>输出看起来像这样</p>
<pre><code> Enter message to be ciphered: hello
Enter the private key: \@154>
key is '10111001000000110001110101110100111110'
encrypted text is '11010001100101110110011011001101111'
False
False
False
False
False
</code></pre>
<p>我搞砸的是,试图将这两个二进制(密钥和加密)进行比较,并给出true(1)或false(0)。然后,xor应该给我一个结果为1和0的二进制列表,这两个列表是通过比较得到的。有什么意见吗?</p>