擅长:python、mysql、java
<p>使用另一个答案来修复代码:</p>
<pre><code>m = []
for url in urllist:
try:
file = urllib2.urlopen (url)
urlstring = file.read ()
m = re.findall (r'file:///\\results.cal.ci.spirentcom.com\\smt\\SCMSmartTest\\\d+.\d+\\BLL\d+_IL\d+\\.*?\\TC\S+tcl',
urlstring)
copyFileCounts = 1
except IOError as e:
print "Can't open URL: {}".format(e.message)
</code></pre>
<p>做这件事并请求原谅是一个很好的做法,所以做任何你想做的事,然后抓住错误</p>