掷硬币问题的Python代码

Question

我用python编写了一个程序，它模拟了100次抛硬币，并给出了抛硬币的总数。问题是我还想打印正面和反面的总数。

这是我的代码：

import random
tries = 0
while tries < 100:
    tries += 1
    coin = random.randint(1, 2)
    if coin == 1:
        print('Heads')
    if coin == 2:
        print ('Tails')
total = tries
print(total)

我绞尽脑汁想办法，但到目前为止什么都没有。除了投球的总数外，还有没有办法印出正面和反面的数目？

Answer 1

import random

samples = [ random.randint(1, 2) for i in range(100) ]
heads = samples.count(1)
tails = samples.count(2)

for s in samples:
    msg = 'Heads' if s==1 else 'Tails'
    print msg

print "Heads count=%d, Tails count=%d" % (heads, tails)

Answer 2

您有一个尝试次数的变量，它允许您在结尾处打印，所以只需对头和尾的次数使用相同的方法。在循环外创建一个heads和tails变量，在相关的if coin == X块内递增，然后在最后打印结果。

Answer 3

import random

total_heads = 0
total_tails = 0
count = 0


while count < 100:

    coin = random.randint(1, 2)

    if coin == 1:
        print("Heads!\n")
        total_heads += 1
        count += 1

    elif coin == 2:
        print("Tails!\n")
        total_tails += 1
        count += 1

print("\nOkay, you flipped heads", total_heads, "times ")
print("\nand you flipped tails", total_tails, "times ")