Python BS4删除所有div ID的类、样式

Question

我正在尝试用BS4解析来自站点的html内容。我得到了我的html片段，但我需要删除所有的标签类，ID，样式等等

例如：

<div class="applinks">
<div class="appbuttons">
<a href="https://geo.itunes.apple.com/ru/app/cloud-hub-file-manager-document/id972238010?mt=8&amp;at=11l3Ss" rel="nofollow" target="_blank" title="Cloud Hub - File Manager, Document Reader, Clouds Browser and Download Manager">Загрузить</a>
<span onmouseout="jQuery('.wpappbox-8429dd98d1602dec9a9fc989204dbf7c .qrcode').hide();" onmouseover="jQuery('.wpappbox-8429dd98d1602dec9a9fc989204dbf7c .qrcode').show();">QR-Code</span>
</div>
</div>

我需要得到：

^{pr2}$

我的代码：

# coding: utf-8
import requests
from bs4 import BeautifulSoup


url = "https://lifehacker.ru/2016/08/29/app-store-29-august-2016/"
r = requests.get(url)
soup = BeautifulSoup(r.content)
post_content = soup.find("div", {"class","post-content"})
print post_content

如何删除所有标记属性？在

Answer 1

import requests
from bs4 import BeautifulSoup


url = "https://lifehacker.ru/2016/08/29/app-store-29-august-2016/"
r = requests.get(url)
soup = BeautifulSoup(r.content)
for tag in soup():
    for attribute in ["class"]: # You can also add id,style,etc in the list
        del tag[attribute]

Answer 2

要从报废数据中的标记中删除所有属性，请执行以下操作：

import requests
from bs4 import BeautifulSoup

def CleanSoup(content):
    for tags in content.findAll(True): 
        tags.attrs = {}
    return content


url = "https://lifehacker.ru/2016/08/29/app-store-29-august-2016/"
r = requests.get(url)
soup = BeautifulSoup(r.content,"html.parser")
post_content = soup.find("div", {"class","post-content"})
post_content = CleanSoup(post_content)